If (x+2) is a factor of x^5-4a²x²+2x+2a+3, find the value of a.
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since x + 2 is a factor, substitute x = - 2, we get
-32 -16 a2 -4 + 2a + 3 = 0 or 16a2 -2a + 33 =0
a does not have real value
-32 -16 a2 -4 + 2a + 3 = 0 or 16a2 -2a + 33 =0
a does not have real value
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