If x+2 is a factor
of x²+ax+8 then a=
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Hey mate here is your answer:
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→Let,
→p(x) = x² + ax + 8 ,
Given : x + 2 is factor of p(x) ,
→ x + 2 = 0 ,
→ x = -2,
Then by factor theorem p( -2 ) = 0 ,
→ p( x ) = x² + ax + 8 ,
→ p( -2 ) = ( -2 )² - 2a + 8 = 0 ,
→ 4 - 2a + 8 = 0 ,
→ 12 - 2a = 0 ,
→2a = 12 ,
→a = 6 ✓.
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Hope it helps you.
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