Question

If x-2 is a factor of x3-2ax2 + ax-8, find the value of a

Answer 1

if x-2 is the factor of given polynomial then remander = 0

so finding the remainder
$p(x) = x {}^{3} - 2ax {}^{2} + ax - 8 \\ x - 2 = 0 \\ x = 2 \\ putting \: x = 2 \\ p(2) = 8 - 8a + 2a - 8 \\ p(2) = - 6a \\ - 6a = 0 \\ a = 0$

Answer 2

Hey dear friend

If x-2 is a factor of eq.(x³-2ax²+ax-8)

Substituting x =2 in eq.
we get

=>2³-2a2²+2a-8=0
=>8-8a+2a-8=0
=>-6a=0
=>a=0

perfectly fine pure correct answer
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