If x-2 is a factor of x³-3x+5a then the value of a is what
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3
Answer:
a=-2/5
Step-by-step explanation:
1st method
x-2)x^3 -3x +5a (x^2+2x+1
x^3 -2x^2 (to substract put-vesignin x^3-2x^2)
_________
2x^2 -3x + 5a
2x^2 -4x
______________
x + 5a
x - 2
________
5a+2
since x-2 is a factor of x³-3x+5a
so 5a+2=0
a= -2/5
2nd method
since x-2 is a factor of x³-3x+5a
so put x=2 in x³-3x+5a=0
8-6+5a=0
2+5a=0
a=-2/5
rakhithakur
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