if (x-2) is a factor of x3+ax2+bx+16 and a-b=6 then find the value of a and b
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a= -2
b= -8
equations will be
2a+b= -12 -1
a-b=6
you will get the ans by substitution
b= -8
equations will be
2a+b= -12 -1
a-b=6
you will get the ans by substitution
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