If x-2 is a factor of x³+ax²+bx+16 and a-b equal to 6 find a and b
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Since (x-2) is a factor of x^3+ax^2+bx+16
By synthetic division method
2a+B+12=0
also given a-b=6
From above a=(-2) and B=(-8)
By synthetic division method
2a+B+12=0
also given a-b=6
From above a=(-2) and B=(-8)
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