Question

If x-2 is a factor of x3+ax2+bx+16 and b=4a find the value of a and b

Answer 1

Answer:

(-11/8), (-11/2)

Step-by-step explanation:

put x-2 = 0

x=2

put it in equation,

2*3+a*2*2+b*2+16=0

4a+2b= -22

because b=4a

hence,  4a+2*4a = -22

16a = -22

a = (-22/16) = (-11/8)

b = 4* (-(11/8)

  b = (-11/2)