Question

If (x-2) is a factor of x³-mx²+10x-20, find the value of m p(2) = x³-mx²+10x-20
where p(2) = 0
x=2
p(2) = ___-m__+___+10__-20
0 = ___-m__+___-20
0 = ___-2m
2m = ____
m = _______
pls give the right answer
std lX ​

Answer 1

Answer:

m = 2

Step-by-step explanation:

p(x) = x³-mx²+10x-20

given, p(2) = 0, then

2³-m(2)²+10(2)-20=0

8-4m+20-20=0

4m = 8

m = 2.