Question

If x-2 is a factor of x3 -mx2 + 10x-20 then find the value of m​

Answer 1

Step-by-step explanation:

x-2=0

x=2

x3-mx2+10x-20=0

2*3-m*2*2+10*2-20=0

6-4m+20-20=0

-4m=-6

m=-6/-4

Answer 2

To Find :-

• The value of m.

Solution :-

Given,

• x - 2 is a factor of p(x) = x³ - mx² + 10x - 20.

Put divisor is equal to zero,

⟶ x - 2 = 0

⟶ x = 2

Let, p(x) = x³ - mx² + 10x - 20

[ Putting x = 2 ]

⟶ p(2) = (2)³ - m(2)² + 10(2) - 20

⟶ p(2) = 8 - 4m + 20 - 20

⟶ p(2) = 8 - 4m + 0

⟶ p(2) = 8 - 4m

Thus, remainder = p(2) = 8 - 4m

Since, x - 2 is a factor of p(x) = x³ - mx² + 10x - 20.

.°. Remainder is zero.

⟶ 8 - 4m = 0

⟶ -4m = 0 - 8

⟶ -4m = -8

⟶ 4m = 8

⟶ m = 2

Therefore,

The value of m is 2.