Question

If (x-2) is a factor of xsquare - 3ax+3a-7 then find the value of a

Answer 1

let f(x)=x²-3ax+3a-7
given (x-2) is a factor of(1) so f(2)=0
substitute x=2 in (1)
we get 2²-3a(2)+3a-7=0
4-6a+3a-7=0
3a=4-7
a=-3/3
a=-1.
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