Question

If x = 2 is a root of ax^2 + ax + 6 = 0, find the value of a.

Answer 1

Step-by-step explanation:

ax

2

+ax+3=0

x=1 is a root of the equation

a+a+3=0

2a=−3

a=

2

−3

x

2

+x+b=0

x=1 is root

1+1+b=0

b=−2

∴ab=

2

−3

×−2

ab=3

Answer 2

ax² + ax + 6 = 0

a(2)² + 2a + 6 = 0 [•x = 2]

4a + 2a + 6 = 0

6a = -6

a = -1