if x=2 is a root of q polynomial f(x) = 2x-3x+7a find the value of a
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x=2
f (2)=2×(2)-3 (2)+7a = 0
f (2)=4 - 6 + 7a = 0
= -2 + 7 a = 0
7a = 2
a = 7 ÷ 2
a = 3.5
f (2)=2×(2)-3 (2)+7a = 0
f (2)=4 - 6 + 7a = 0
= -2 + 7 a = 0
7a = 2
a = 7 ÷ 2
a = 3.5
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if x=-1/2 is a root of the polynomial p(x) = 8cube -axsquare -x+2
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