Question

If x=2 is a root of the equation 3x² – 2kx + 5 = 0, then k is equal to :
A 4/17
B 17/4
C 1/17
D 1/4

Answer 1

k = 17/4

Step-by-step explanation:

3(4) - 2(2)k + 5 = 0

12+5-4k=0

17-4k=0

-4k=-17

k=17/4

Answer 2

Answer:

B)17/4

Step-by-step explanation:

p(x) = 3x^2 - 2kx + 5 = 0

p(2) = 3(2)^2 - 2(2)k + 5 = 0

= 12 - 4k + 5 = 0

. = -4k = -17

= k = -17/-4

k = 17/4