CBSE BOARD X, asked by arbaz7243, 9 months ago

If x=2 is a root of the equation 3x2-px-2 =0. Then the value of p is

Answers

Answered by ashauthiras
2

Answer:

3x∧2-px-2=0

1 root=2

3(2∧2)-2p-2=0

3*4-2=2p

2p=12-2

p=10/2

p=5

3x∧2-5x-2=0

3x∧2-6x+x-2=0

3x(x-2)+1(x-2)=0

(x-2)(3x+1)=0

x=-1/3(2nd root)

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