Math, asked by ashunigam42, 7 months ago

If
x=2 is a root of the Polynomial
p(x) = 2x²-3x+7a, find the value of a solve this bro and sis please help ​

Answers

Answered by Anonymous
1

Answer:

Given that x=2,

p(x)= 2x^{2} -3x+7a\\=2(2)^{2} - 3(2)+7a\\=2(4)-6+7a\\=8-6+7a\\=2+7a\\-2=7a\\\frac{-2}{7} =a\\

hope that was useful

Answered by Anonymous
0

Answer:

Here is your answer.

Given that x=2,

\begin{gathered}p(x)= 2x^{2} -3x+7a\\=2(2)^{2} - 3(2)+7a\\=2(4)-6+7a\\=8-6+7a\\=2+7a\\-2=7a\\\frac{-2}{7} =a\\\end{gathered}

Please Mark Me as Brainliest ❤️...

Similar questions