Question

if x=2 is a root of the Q.eqn 3x²-px-2=0,then value of 'p'is (a)1 (b) -2a/b(c). 0 (d) 5​

Answer 1

d)

$p = 5$

Explanation:

Since x = 2 is a root of the equation, this value of x will satisfy the equation,so

$3 \times {2}^{2} - p \times 2 - 2 = 0$

$12 - 2p - 2 = 0$

$10 - 2p = 0$

$2p = 10$

$p = 5$

Answer 2

Answer:

$\huge\colorbox{yellow}{ \tt{answer} \: : }  \\ \begin{gathered} \large \tt \underbrace{Let's \: \: solve} \\ \\ \\\begin{gathered}a{}^{2} x {}^{2} - 3abx + 2b {}^{2} = 0\\ \\ = > a {}^{2} x {}^{2} - abx -2abx + 2b {}^{2} = 0 \\ \\ = > ax(ax - b) - 2b(ax - b) = 0 \\ \\ = > (ax - b)(ax - 2b) = 0 \\ \\ = > ax - b= 0 \: \: or \: \: ax - 2b = 0 \\ \\ = > x = \frac{b}{a} \: \: or \: \: x =\frac{2b}{a} \end{gathered}\end{gathered} \\ \huge \tt \color{blue} \: \: \frac{2b}{a}$