Math, asked by jitendradhami13, 6 months ago

If x=2 is a solution of kx² + 2 x - 3 =0 the value of k is​

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Answered by sai1484
1

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Answered by Anonymous
3

Answer:

kx {}^{2}  + 2x - 3 = 0 \\ k(2 {}^{2}) + 2 \times 2 - 3 = 0 \\ 4k + 4 - 3 = 0 \\ 4k + 1 = 0 \\ 4k =  - 1 \\ k =  - 1 \div 4

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