If x=✓2 is a solution of kx²+✓2x-4=0 then find the value of k
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Hi there!!!
Given that x = √2 is the solution of kx² + √2x - 4 = 0
We have to find the value of k,
To find, put x = √2 in the equation
⇒ k (√2)² + √2 (√2) - 4 = 0
⇒ k (2) + 2 - 4 = 0
⇒ 2k - 4 = 0
⇒ 2k = 2
⇒k = 1
Hence the value of k is 1.
HOPE IT HELPS!!!
Given that x = √2 is the solution of kx² + √2x - 4 = 0
We have to find the value of k,
To find, put x = √2 in the equation
⇒ k (√2)² + √2 (√2) - 4 = 0
⇒ k (2) + 2 - 4 = 0
⇒ 2k - 4 = 0
⇒ 2k = 2
⇒k = 1
Hence the value of k is 1.
HOPE IT HELPS!!!
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