Math, asked by fa8571706, 4 months ago

if x= - 2 is a solution of the equation x^2= - 2 + px + 8 = 0 what is the value of p​

Answers

Answered by Anonymous
0

Step-by-step explanation:

given \:  \: x =  - 2 \\  {x}^{2}  =  - 2 + px + 8 = 0 \\  - x {}^{2}  - 2 + px  + 8 =  \\  - ( - 2) {}^{2}  - 2 + p( - 2) + 8 = 0 \\  - 4 - 2 - 2p + 8 = 0 \\ - 6 + 8 - 2p = 0 \\ 2 - 2p = 0 \\ 2 = 2p \\  \frac{2}{2}  = p \\  \\ 1 = p

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Answered by pkrai1271975
0

Answer:

4

Step-by-step explanation:

-2+px +8=0

p=-2+-2+8

p= -4+8

p= 4

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