If x=2 is a zero of polynomial x^2-2k+2, then the value of k is_____
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Answer:
k=1 by zero of the polynomial
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Step-by-step explanation:
=p(x) = x^2-2k+2
=p(2) = (2)^2 - 2k + 2
= 0 = 4+2 - 2k
=2k=6
k = 6/2
k = 3
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