If (x-2) is a zero of x³-4x²+kx-8, find k.
help me
Answers
Answered by
1
Answer:If x-2 is a factor then x-2=0
x=2
Putting the value of x in the equation
P(x)=x3-4x2-kx-8
P(2)=(2)3-4(2)2-k(2)-8
P(2)=8-16-2k-8
We know that 2 is a factor therefore the whole equation will be equal to zero on putting the value of x as 2
P(2)=8-16-2k-8=0
=-16-2k=0
-2k=16
k=16/-2
k=-8
Your answer
Step-by-step explanation:
Answered by
1
Answer: k=-8
Step-by-step explanation: f x-2 is a factor then x-2=0
x=2
Putting the value of x in the equation
P(x)=x3-4x2-kx-8
P(2)=(2)3-4(2)2-k(2)-8
P(2)=8-16-2k-8
We know that 2 is a factor therefore the whole equation will be equal to zero on putting the value of x as 2
P(2)=8-16-2k-8=0
=-16-2k=0
-2k=16
k=16/-2
k=-8
Your answer
Similar questions