If (x-2) is factor of x^2+ax-6=0 and x^2-9x+b=0 then a+b is equal to
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Answer:
Since, (x -2) is one factor of x
2
+ax−6=0
⇒2
2
+a(2)−6=0
⇒2a=2⇒a=1 ...(i)
Again as (x -2) is factor of x
2
−9x+b=0
⇒2
2
−9(2)+b=0
⇒b=14 ...(ii)
Now, a+b=1+14=15
Hence, Option A is correct.
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