If x + 2 is factor of x3 + 2ax2 + ax - 1 then value of a is
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Step-by-step explanation:
given,
(X)^3+2a(x)^2+ax-1 = f(x) = 0
(x+2) is a factor of f(x)
x+2 = 0
x = -2
substitute x = -2 in polynomial f(x)
f(-2) = (-2)^3+2a(-2)^2+a(-2)-1
0 = -8+8a-2a-1
0 = 6a-9
6a = 9
a = 3/2
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