If x=2 is one root of the equation( k-3)x^2-kx-8=0. Find k
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Answered by
3
Answer:
(k-3)4-k×2-8 = 0
4k-12-2k-8=0
4k-2k=12+8
2k=20
k=20÷2
k= 10
10 is your answer
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Answered by
1
Answer:
10 is ur answer
Step-by-step explanation:
(k-3)4-k×2-8=0
4k-12-2k-8=0
4k-2k=12-8
2k=20
k=20÷2
k=10
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