Question

if x=2 is one root of the equation (k-3)x²-kx -8=0 , find the value of k. also find the other root of equation.

Answer 1

$since \: x = 2 \: is \: a \: rootof \: the \: equation \\ (k - 3) {2}^{2} - 2k - 8 = 0 \\ 4(k - 3) - 2k - 8 \\ 4k - 12- 2k - 8 = 0 \\ 2k = 20 \\k = 10$

the equation will then become

$7{x}^{2} - 10x - 8$

let the other root be a

sum of roots = - b/a

2+ a = 10/7

a = 10/7 - 2

a = - 4/7

Answer 2

Answer:

K = 10

x = -4/7

Step-by-step explanation:

please refer to the picture attached