if x=2 is one root of the quadratic equation xsquare-2Kx-6=0, then find the value of K.
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Answer:
x^2-2kx-6=0
on putting the value of x we get
(2)^2-2×k×2-6=0
4-4k-6=0
-2-4k=0
-2=4k
k=-1/2
Answered by
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x=2
x^2 -2Kx-6=0
2^2-2×2K-6=0
4-4K-6=0
-2-4K=0
-4K=2
K=2/-4
K=-1/2
K=-0.5
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