Question

If x=2 is one root of x^3+2x^2-3x-6=0,then find the other roots of the equation​

Answer 1

Step-by-step explanation:

p(x) = x^3 + 2x^2 - 3x - 6

p(2) = 8 + 8 - 6 - 6

p(2) = 16 - 12 = 4

So x - 4 is another factor of p(x) = x^3 + 2x^2 - 3x - 6.

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