If x=2 is one root of x^3+2x^2-3x-6=0,then find the other roots of the equation
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Step-by-step explanation:
p(x) = x^3 + 2x^2 - 3x - 6
p(2) = 8 + 8 - 6 - 6
p(2) = 16 - 12 = 4
So x - 4 is another factor of p(x) = x^3 + 2x^2 - 3x - 6.
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