if x=√2 is solution of x^2+kx-4=0 then find value of k
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Hi!!
(√2)² +k ( √2 ) - 4 = 0
k √2 = 0
k = 0
Hope it helps!!
(√2)² +k ( √2 ) - 4 = 0
k √2 = 0
k = 0
Hope it helps!!
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