Question

If (x - 2) is the factor of the polynomial f(x) = (x³ + ax² + bx+6) and (x-3) is the factor of polynomial f(x) - 3, then f(x) = OPTIONS A) f(x) = x ^ 3 + 3x ^ 2 - 1x - 6 B) f(x) = x ^ 3 - 3x ^ 2 - 1x + 6 c) f(x) = x ^ 3 - 3x ^ 2 - 1x - 6 D) f(x) = x ^ 3 - 3x ^ 2 + 1x + 6​

Answer 1

Answer:

option B

Step-by-step explanation:

by option checking

let's check option B

f(x)=x^3-3x^2-x+6

given f (x)=0 when x=2

f (2)=2^3-3(2)^2-2+6

=8-12-2+6

=0

and given f (x)-3=0 when x=3

f (3)-3=3^3-3 (3)^2-3+6-3

=27-27-6+6

=0

hence option B is correct