Question

If x-2 is the factor of x3-3x+5 a then find the value of a

Answer 1

Hola !

Here is your answer

Let p(x) = x^3 -3a + 5

q(x) = x - 2

x - 2 = 0

x = 2

substitute x = 2 in p(x)

thus, 2^3 -3a + 5

8 -3a + 5

13 -3a = 0

Here we take zero as it's factor and it's completely divisible.

Thus, -3a = -13

a = -13/-3

a = 13 / 3

Hope it helps !

Answer 2

Given:

Polynomial: x3-3x+5a

Factor: (x-2)

To find:

The value of a

Solution:

The value of a is -2/5.

We can find the value by following the given steps-

We know that the factor of a polynomial is the value of the variable that makes the value of the polynomial equal to zero.

So, on putting the factor equal to 0 we will get the value of x for which the polynomial is equal to 0.

The factor=x-2

x-2=0

x=2

So, on putting x=2 in the given polynomial, the polynomial will be equal to 0.

Now we will put the value of x to find a.

The given polynomial is $x^{3} -3x+5a$.

P(2)= $2^{3} -3(2)+5a$

Also, P(2)=0

8-6+5a=0

2+5a=0

5a= -2

a= -2/5

Therefore, the value of a is -2/5.