If( x+2) is the factor of x³-ax²-bx+4 then the value of (b-2a) is
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since,x+2 is a factor of a polynomial p(x) =x³-ax²-bx+4
so,p(-2)=0
(-2)³-a(-2)²-b(-2)+4=0
-8-4a+2b+4=0
-4-4a+2b=0
2(-2-2a+b)=0
-2-2a+b=0
b-2a=2
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