if x + 2 k is a factor of f(x) =x^4- 4 k^2+x^2 + 2 x + 3 k + 3 find k
Answers
Answered by
2
hey !!!
x + 2 = 0
x = -2
f(x) = x⁴ - 4k² + x² + 2x + 3k + 3
f(-2) = (-2)⁴ - 4k² + ( -2) ² +2 ( - 2) + 3k + 3
=> 16 - 4k² + 4 -4 + 3k + 3
=> - 4k² +3k + 19
=> now by using quadratic formula ..
roots = -b +- (√b²-4ac /2a
roots = -3 +-(√3²- 4(-4)×19/2×-4
roots = -3 +-(√9-304/-8
roots = -3 +-√-295/-8
1 value of k '= -3+(√-295/ -8
k = -( 3 +√295 ) /-8
k = (3 +√295)/8
and 2nd value of k = -3 - (√-295 /-8
k = -3 + 295/-8
k = -( 3 -√295/ -8
k = 3 - √295/ 8
hope it helps !!!
₹Rajukumar111
x + 2 = 0
x = -2
f(x) = x⁴ - 4k² + x² + 2x + 3k + 3
f(-2) = (-2)⁴ - 4k² + ( -2) ² +2 ( - 2) + 3k + 3
=> 16 - 4k² + 4 -4 + 3k + 3
=> - 4k² +3k + 19
=> now by using quadratic formula ..
roots = -b +- (√b²-4ac /2a
roots = -3 +-(√3²- 4(-4)×19/2×-4
roots = -3 +-(√9-304/-8
roots = -3 +-√-295/-8
1 value of k '= -3+(√-295/ -8
k = -( 3 +√295 ) /-8
k = (3 +√295)/8
and 2nd value of k = -3 - (√-295 /-8
k = -3 + 295/-8
k = -( 3 -√295/ -8
k = 3 - √295/ 8
hope it helps !!!
₹Rajukumar111
Similar questions