Question

If x=2-k, y=3+k are the solution of linear equation 3x-2y+5=0,then find the value of k also, find value of x and y.

Answer 1

Answer:

The answer is k=1,x=1,y=4k=1,x=1,y=4

Step-by-step explanation:

Substitute x=2-kx=2−k and y=3+ky=3+k , the given equation 3x-2y+5=03x−2y+5=0

\begin{gathered}\Rightarrow 3(2-k)-2(3+k)+5=0\\\Rightarrow 6-3k-6-2k+5=0\\\Rightarrow -5k+5=0\\\Rightarrow 5=5k\\\Rightarrow k=1\end{gathered}

⇒3(2−k)−2(3+k)+5=0

⇒6−3k−6−2k+5=0

⇒−5k+5=0

⇒5=5k

⇒k=1

Therefore x=2-1=1,y=3+1=4x=2−1=1,y=3+1=4

Answer 2

x=1, y=4

explanation: given, x= 2-k   ;  y=3+k

  3x-2y+5=0

  putting the values of x and y

3(2-k) -2(3+k) + 5= 0

6-3k -6-2k + 5= 0

5k=5

k=1

putting the value of k in the given parts we get

x=2-1             y=3+1

x=1                  y=4