If x= 2–k, y= 3+k, are the solution of the linear equation 3x–2y +5=0, then find the value of 'k' also find the values
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Answer:
k=1, x=1 , y=4
Step-by-step explanation:
since x=2-k & y=3+k are soution of the equation
3x-2y +5=0 .... 1
putting values of x and y in 1
3(2-k)-2(3+k)+5=0
6-3k-6-2k=(-5)
-5k+0=(-5)
k=1
Since value of k is 1
therefore value of x =2-k=2-1=1
x=1
& y=3+k=3+1=4
y=4
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