Question

If x=-2,kx²+x-6=0 fnd the value of k

Answer 1

Answer:

Given, x = - 2

so

kx^2 + x - 6 = 0

putting back the value of x , we get :

$k( - 2)^{2} + ( - 2) - 6 = 0 \\ \\ = > 4k - 2 - 6 = 0 \\ \\ = > 4k - 8 = 0 \\ \\ = > 4k = 8 \\ \\ = > k = \frac{8}{4} \\ \\ = > k = 2$

hope it helps uH ✔

Answer 2

Answer:

−x+6/x2

Step-by-step explanation:

Let's solve for k.

kx2+x−6=0

Step 1: Add -x to both sides.

kx2+x−6+−x=0+−x

kx2−6=−x

Step 2: Add 6 to both sides.

kx2−6+6=−x+6

kx2=−x+6

Step 3: Divide both sides by x^2.

kx2/x2=−x+6/x2

k=−x+6/x2

Answer:

k=−x+6/x2