if x^2+mx+20=(x+5)(x+4) find the value of m
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Answer:
x^2 + mx + 20 = x^2 + 4x + 5x + 20
x^2 + mx + 20 = x^2 + 9x + 20
[ cancelling from both sides i.e., x^2 and 20 ]
mx = 9x
m = 9x /x
m = 9
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