if x^2 + mx -30 = (x-5) (x-6) then m is
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have not one but two answers for you.
It is how you answer this problem, is the answer you get:
x² + 3mx + 6
>>>> I am using complete the square in reverse>>>
We have 6 which can be basically (their are many-many more) broken down into 6 x 1 = 6 or 2 x 3 = 6.
(x + 1)((x + 6) = x 2 + 7x + 6 = 0 ,
7x = 3mx, ==> 7 = 3m, ==> m = 7/3
(x + 2)(x + 3) = x 2 + 5x + 6 = 0 ,
5x = 3mx,==> 5 = 3m,==> m = 5/3
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