If x =2 one root of the equation 5x^2-kx+4=0, find the value of k
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Answered by
1
by pitting values of x=2 in eqn
we get k=12
we get k=12
Answered by
1
given x=2 is a root of 5x^2-kx+4=0
so, 5(2)^2-2K+4=0
5(4)-2k+4=0
24-2k=0
2k=24
k=12
therefore the value of k is 12
so, 5(2)^2-2K+4=0
5(4)-2k+4=0
24-2k=0
2k=24
k=12
therefore the value of k is 12
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