Question

If (x^2-p^2)=(4+p)(4-p) What is the value of x?

Answer 1

Answer:

Value of x is X+ 2= 7 like Variable

Answer 2

Answer:

x^2-p^2 = 16-p^2

Here two -p^2 are cancelled

x^2 = 16

$\sqrt{x} = \sqrt{16}$

x= 4

Step-by-step explanation:

Therefore value of x is 4

Hope it helps you