If |x−2|=p, where x<2, then x−p = (A) −2 (B) 2 (C) 2−2p (D) 2p−2 (E) |2p−2|
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Answer:
|x − 2| = 2 − x.
Case 1: x = p + 2
Case 2: x = 2 - p
x - p
Case 1: p + 2 - p = 2
Case 2: 2 - p - p = 2 - 2p
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