Question

If X^2+PX_30=(X_5)(X+6)Then Thè value of p​

Answer 1

Step-by-step explanation:

x^2+px-30= (x-5)(x+6)

x^2+px-30= x^2+6x-5x-30

x^2+px-30-x^2+30=x

px=x

p=x/x

p=1