Question

if (x^2+px-39) and it's one factor is (x-3) so p=?

Answer 1

Your answer !!

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${x}^{2} + px - 39 = 0 \\ \\ x - 3 = 0 \\ \\ x = + 3 \\ \\Put\: value \:of \:x\: in\: the\:given\: polynomial \\ \\ {3}^{2} + p ( 3 ) - 39 = 0 \\ \\ 9 + 3 p - 39 = 0 \\ \\ 3 p - 30 \\ \\ 3 p = + 30 \\ \\ p = \frac{30}{3} \\ \\p = 10$

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Answer 2

your ques is solved.