if x = 2 root 3 + 2 root 2 , find (x+1/x) whole square
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Answer:
Hi ,
x = 2 - √3--( 1 )
1/x = 1/( 2 - √3 )
= ( 2 + √3 ) / [ ( 2 - √3 )(2 + √3 ) ]
= ( 2 + √3 ) / [ 2² - ( √3 )² ]
= ( 2 + √3 ) / ( 4 - 3 )
= 2 + √3 ----( 2 )
x - 1/x
= 2 - √3 - ( 2 + √3 )
= 2 - √3 - 2 - √3
= - 2√3 ---( 3 )
Therefore ,
( x - 1/x )³ = ( - 2√3 )³
= - 24√3
I hope this helps you.
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Answer:
Answer:
1/x= (1/2) (√3-√2), x+1/x= (1/2) [5√3+2√3]
Step-by-step explanation:
x= 2√3+2√2.
=> 1/x= 1/ 2(√3+√2) on rationalizing
= (√3-√2) / 2
again , x+1/x= 2(√3+√2) + (√3-√2) /2
= (5/2)√3 + (3/2)√2
=( 1/2)[ 5√3+2√3]