Question

if x=2- root 3 find the value of (x+1/x) the whole raised to 3

Answer 1

Answer:

64

Step-by-step explanation:

x=2-√3

1/x=1/(2-√3)

multiplying and dividing by 2+√3 We get

1/x= 2+√3

So, x+1/x=4

cube of the same is 64

Answer 2

Answer:

$x = 2 - \sqrt{3} \\ \\ value = (x + \frac{1}{x}) \\ \\ = 2 - \sqrt{3} + \frac{1}{2 - \sqrt{3} } \\ \\ = (2 - \sqrt{3} )^{2} + 1 \div 2 - \sqrt{3} \\ \\ \\ \\ = \frac{4 + 3 - 4 \sqrt{3 } + 1}{2 - \sqrt{3} } \\ \\ \\ = \frac{8 - 4 \sqrt{3} }{2 - \sqrt{3} } \\ \\ \\ = \frac{4(2 - 4 \sqrt{3}) }{2 - 4 \sqrt{3} } \\ \\ \\ = 4$

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