Question

if x = 2- root 3 find the value of x +1/x whole cube
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Answer 1

Answer:

(x+1/x)^3=4

Step-by-step explanation:

answer is in the above picture

Answer 2

Answer:

$Given,\ x=2-\sqrt3} \\=\frac{1}{x} = \frac{1}{(2-\sqrt3) } } \\=\frac{2+\sqrt3}{(2-\sqrt3)(2+\sqrt{3}) } \\=\frac{2+\sqrt3}{2^{2}-(\sqrt{3})^{2}  }\\=\frac{2+\sqrt3}{4-3} \\=\frac{2+\sqrt3}{4-3} \\=\frac{2+\sqrt3}{1}\\={2+\sqrt3}$

$x+\frac{1}{x} \\=2-\sqrt{3} +(2+\sqrt{3} )\\=2-\sqrt{3} +2+\sqrt{3} \\=4$

⇒$(x+\frac{1}{x}) ^{3}=4^{3}=64$

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