If x=2+root 3, find the value of x cube + 1 upon x cube ?
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x = 2 + ∫3 , 1/x = 2-∫3
So, x + 1/x = 4
(x+1/x)3 = 43
x3 + 1/x3 + 3x + 1/x = 64
x3 + 1/x3 + 3 = 64
x3 + 1/x3 = 64 – 3 = 61
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