Question

if x=2+ root 3 find (x + 1/x) cube
please tell fast urgent​

Answer 1

Answer:

$x = 2 + \sqrt{3} \\ \therefore \: ({ \frac{x + 1}{x}) }^{3} \\ = ( { \frac{2 + \sqrt{3} + 1 }{2 + \sqrt{3} }) }^{3} \\ = ( { \frac{3 + \sqrt{3} }{2 + \sqrt{3} } )}^{3}$

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