Question

If x = 2 - root 3, then find the value of 4x + 4/x

Answer 1

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x + 1/x = 2 + root3 + 2 - root3

=> x + 1/x = 4

On squaring both sides, we get

x^2 + 1/x^2 + 2(x)(1/x) = 16

=> x^2 + 1/x^2 + 2 = 16

=> x^2 + 1/x^2 = 14

Again, on squaring both sides, we get

x^4 + 1/x^4 + 2 (x^2) (1/x^2) = 196

=> x^4 + 1/x^4 + 2 = 196

=> x^4 + 1/x^4 = 194

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Answer 2

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x + 1/x = 2 + root3 + 2 - root3

=> x + 1/x = 4

On squaring both sides, we get

x^2 + 1/x^2 + 2(x)(1/x) = 16

=> x^2 + 1/x^2 + 2 = 16

=> x^2 + 1/x^2 = 14

Again, on squaring both sides, we get

x^4 + 1/x^4 + 2 (x^2) (1/x^2) = 196

=> x^4 + 1/x^4 + 2 = 196

=> x^4 + 1/x^4 = 194

________________________________________________

#нσρє íт нєℓρѕ♡~

#мαяк αѕ вяαíηℓíѕт☘️