If x= 2-root 3 then find the value of( x + 1/x)³
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Answer:
64
Solution:
We have ;
x = 2 - √3
Thus,
1/x = 1/(2 - √3)
Now,
Rationalising the denominator in RHS , we have ;
=> 1/x = (2 + √3)/(2 - √3)(2 + √3)
=> 1/x = (2 + √3)/{2² - (√3)²}
=> 1/x = (2 + √3)/(4 - 3)
=> 1/x = (2 + √3)/1
=> 1/x = 2 + √3
Now,
=> x + 1/x = 2 - √3 + 2 + √3
=> x + 1/x = 4
=> (x + 1/x)³ = 4³
=> (x + 1/x)³ = 64
Hence,
The required value of (x + 1/x)³ is 64 .
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