Question

if x = 2 + root 3 then find X square + 1 by x square

Answer 1

Answer:

2

Step-by-step explanation:

answer 2....................

Answer 2

Answer:

14

Step by step explanation:

we have,

x=2+√3

Hence,

$\frac{1}{x} = \frac{1}{2 + \sqrt{3} } \times \frac{2 - \sqrt{3} }{2 - \sqrt{3} }$

$\frac{1}{x } = 2 - \sqrt{3}$

$x + \frac{1}{x} = 2 + \sqrt{3} + 2 - \sqrt{3} \\ x + \frac{1}{x } = 4 \\ squaring \: both \: sides \\ ( {x + \frac{1}{x}) }^{2} = {4}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2.x. \frac{1}{x} = 16 \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 16 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 16 - 2 \\ {x}^{2} + \frac{1}{ {x}^{2} } = 14$